MySQL实现排名并查询指定用户排名功能，并列排名功能

表结构：

CREATE TABLE test.testsort (  id int(11) NOT NULL AUTO_INCREMENT,  uid int(11) DEFAULT 0 COMMENT '用户id',  score decimal(10, 2) DEFAULT 0.00 COMMENT '分数',  PRIMARY KEY (id))ENGINE = INNODBAUTO_INCREMENT = 1CHARACTER SET utf8COLLATE utf8_general_ciCOMMENT = '测试排序'ROW_FORMAT = DYNAMIC;

思路：可以先排序，再对结果进行编号；也可以先查询结果，再排序编号。

说明：

@rownum := @rownum + 1 中 := 是赋值的作用，这句话的意思是先执行@rownum + 1，然后把值赋给@rownum；

(SELECT @rownum := 0) r 这句话的意思是设置rownum字段的初始值为0，即编号从1开始。

实现排名：

方法一：

SELECT  t.*,  @rownum := @rownum + 1 AS rownumFROM (SELECT         @rownum := 0) r,     (SELECT         *       FROM testsort       ORDER BY score DESC) AS t;

方法二：

SELECT  t.*,  @rownum := @rownum + 1 AS rownumFROM (SELECT         @rownum := 0) r,     testsort AS tORDER BY t.score DESC;

结果：

查看指定用户排名：

方法一：

SELECT  b.*FROM (SELECT    t.*,    @rownum := @rownum + 1 AS rownum  FROM (SELECT           @rownum := 0) r,       (SELECT           *         FROM testsort         ORDER BY score DESC) AS t) AS bWHERE b.uid = 222;

方法二:

SELECT  b.*FROM (SELECT    t.*,    @rownum := @rownum + 1 AS rownum  FROM (SELECT           @rownum := 0) r,       testsort AS t  ORDER BY t.score DESC) AS bWHERE b.uid = 222;

结果：

实现并列排名（相同分数排名相同）：

SELECT  obj.uid,  obj.score,  CASE WHEN @rowtotal = obj.score THEN @rownum WHEN @rowtotal := obj.score THEN @rownum := @rownum + 1 WHEN @rowtotal = 0 THEN @rownum := @rownum + 1 END AS rownumFROM (SELECT         uid,         score       FROM testsort       ORDER BY score DESC) AS obj,     (SELECT         @rownum := 0,         @rowtotal := NULL) r

查询指定用户并列排名:

SELECT  total.*FROM (SELECT    obj.uid,    obj.score,    CASE WHEN @rowtotal = obj.score THEN @rownum WHEN @rowtotal := obj.score THEN @rownum := @rownum + 1 WHEN @rowtotal = 0 THEN @rownum := @rownum + 1 END AS rownum  FROM (SELECT           uid,           score         FROM testsort         ORDER BY score DESC) AS obj,       (SELECT           @rownum := 0,           @rowtotal := NULL) r) AS totalWHERE total.uid = 222;

文章转载于:https://www.cnblogs.com/woods1815/p/9595494.html

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